Mathematics/General Ability MCQs
Topic Notes: Mathematics/General Ability
MCQs and preparation resources for competitive exams, covering important concepts, past papers, and detailed explanations.
Plato
- Biography: Ancient Greek philosopher (427–347 BCE), student of Socrates and teacher of Aristotle, founder of the Academy in Athens.
- Important Ideas:
- Theory of Forms
- Philosopher-King
- Ideal State
101
450 men have provisions for 40 days at 800g per day. For how many days will the provisions last 600 men consuming 750g per day?
Answer:
32 days
Total provisions = 450 × 40 × 800 = 14,400,000 grams. D2 = 14,400,000 / (600 × 750) = 14,400,000 / 450,000 = 32 days.
102
A garrison has provisions for X men for 30 days. After 10 days, 40 men join, and the remaining food lasts for 16 days. Find X.
Answer:
160
Remaining food after 10 days is for X men for 20 days. It lasts (X + 40) men for 16 days. 20X = 16(X + 40) => 20X = 16X + 640 => 4X = 640 => X = 160.
103
A garrison has food for 350 men. After 15 days, 150 men leave, and the remaining food lasts for 42 days. How many days was the food initially meant to last?
Answer:
39 days
After 15 days, food left lasts 200 men for 42 days. Remaining food = 200 × 42 = 8400 man-days. For 350 men, it would last 8400 / 350 = 24 days. Initial days = 15 + 24 = 39 days.
104
600 men have provisions for 35 days at 700g per day. For how many days will the provisions last 840 men consuming 500g per day?
Answer:
35 days
Total provisions = 600 × 35 × 700 = 14,700,000 grams. D2 = 14,700,000 / (840 × 500) = 14,700,000 / 420,000 = 35 days.
105
A garrison has provisions for X men for 45 days. After 15 days, 60 men join, and the food lasts for 24 days. Find X.
Answer:
240
Remaining food after 15 days is for X men for 30 days. It lasts (X + 60) men for 24 days. 30X = 24(X + 60) => 30X = 24X + 1440 => 6X = 1440 => X = 240.
106
800 men have food for 50 days at 500g per day. For how many days will the food last for 1000 men at 400g per day?
Answer:
50 days
Total food = 800 × 50 × 500 = 20,000,000 grams. D2 = 20,000,000 / (1000 × 400) = 20,000,000 / 400,000 = 50 days.
107
A camp has food for 150 men. After 10 days, 50 more men join, and the food then lasts for 15 days. How many days was the food initially intended to last?
Answer:
30 days
After 10 days, food left lasts 200 men for 15 days. Remaining food = 200 × 15 = 3000 man-days. For 150 men, it would last 3000 / 150 = 20 days. Initial days = 10 + 20 = 30 days.
108
A garrison has provisions for X men for 60 days. After 20 days, 120 men leave, and the remaining food lasts for 48 days. Find the value of X.
Answer:
720
Remaining food after 20 days is for X men for 40 days. It lasts (X - 120) men for 48 days. 40X = 48(X - 120) => 40X = 48X - 5760 => 8X = 5760 => X = 720.
109
A garrison has provisions for 500 men. After 12 days, 100 men leave, and the remaining food lasts for 40 days. Find the number of days the food was initially meant to last.
Answer:
44 days
After 12 days, remaining food lasts 400 men for 40 days. Remaining food = 400 × 40 = 16000 man-days. For 500 men, this would last 16000 / 500 = 32 days. Initial days = 12 + 32 = 44 days.
110
240 men have provisions for 45 days at a rate of 800g per day. For how many days will the provisions last 320 men at 600g per day?
Answer:
45 days
Total provisions = 240 × 45 × 800 = 8,640,000 grams. D2 = 8,640,000 / (320 × 600) = 8,640,000 / 192,000 = 45 days.