Mathematics/General Ability MCQs
Topic Notes: Mathematics/General Ability
MCQs and preparation resources for competitive exams, covering important concepts, past papers, and detailed explanations.
Plato
- Biography: Ancient Greek philosopher (427–347 BCE), student of Socrates and teacher of Aristotle, founder of the Academy in Athens.
- Important Ideas:
- Theory of Forms
- Philosopher-King
- Ideal State
141
A train passes a telegraph pole in 12 seconds and a 600-meter-long bridge in 32 seconds. What is the length of the train?
Answer:
360 meters
Step 1: Let length be L. Speed = L / 12 = (L + 600) / 32. Step 2: 32L = 12L + 7200. Step 3: 20L = 7200, therefore L = 360 meters.
142
A train crosses a signal post in 12 seconds and a 500-meter-long tunnel in 32 seconds. The length of the train is:
Answer:
300 meters
Step 1: Let length be L. Speed = L / 12 = (L + 500) / 32. Step 2: 32L = 12L + 6000. Step 3: 20L = 6000, so L = 300 meters.
143
A train takes 12 seconds to cross a man standing on a platform and 32 seconds to cross a 400-meter-long platform. Find its length.
Answer:
240 meters
Step 1: Let length be L. Speed = L / 12 = (L + 400) / 32. Step 2: 32L = 12L + 4800. Step 3: 20L = 4800, which means L = 240 meters.
144
A train passes a stationary pole in 12 seconds and a 300-meter-long platform in 32 seconds. What is the train's length?
Answer:
180 meters
Step 1: Let length be L. Speed = L / 12 = (L + 300) / 32. Step 2: 32L = 12L + 3600. Step 3: 20L = 3600, giving L = 180 meters.
145
A train crosses an electric pole in 12 seconds and a 200-meter-long bridge in 32 seconds. What is the length of the train?
Answer:
120 meters
Step 1: Let train length be L. Speed = L / 12 = (L + 200) / 32. Step 2: 32L = 12L + 2400. Step 3: 20L = 2400, resulting in L = 120 meters.
146
A train takes 10 seconds to pass a standing man and 25 seconds to pass a 450-meter-long platform. Find the train's length.
Answer:
300 meters
Step 1: Let train length be L. Speed = L / 10 = (L + 450) / 25. Step 2: 25L = 10L + 4500. Step 3: 15L = 4500, therefore L = 300 meters.
147
A train passes a signal pole in 10 seconds and a 375-meter-long platform in 25 seconds. The length of the train is:
Answer:
250 meters
Step 1: Let train length be L. Speed = L / 10 = (L + 375) / 25. Step 2: 25L = 10L + 3750. Step 3: 15L = 3750, meaning L = 250 meters.
148
A train passes a telegraph post in 10 seconds and a 300-meter-long tunnel in 25 seconds. What is the length of the train?
Answer:
200 meters
Step 1: Let train length be L. Speed = L / 10 = (L + 300) / 25. Step 2: Cross multiply: 25L = 10L + 3000. Step 3: 15L = 3000, which means L = 200 meters.
149
A train crosses a pole in 10 seconds and a 225-meter-long bridge in 25 seconds. Find the length of the train.
Answer:
150 meters
Step 1: Let train length be L. Speed = L / 10 = (L + 225) / 25. Step 2: Cross multiply: 25L = 10L + 2250. Step 3: 15L = 2250, giving L = 150 meters.
150
A train passes a stationary pole in 10 seconds and a 150-meter-long platform in 25 seconds. What is the length of the train?
Answer:
100 meters
Step 1: Let train length be L and speed be S. S = L / 10 and S = (L + 150) / 25. Step 2: Equating the two, L / 10 = (L + 150) / 25. Step 3: Cross multiply: 25L = 10L + 1500. 15L = 1500, so L = 100 meters.