Mathematics/General Ability MCQs
Topic Notes: Mathematics/General Ability
MCQs and preparation resources for competitive exams, covering important concepts, past papers, and detailed explanations.
Plato
- Biography: Ancient Greek philosopher (427–347 BCE), student of Socrates and teacher of Aristotle, founder of the Academy in Athens.
- Important Ideas:
- Theory of Forms
- Philosopher-King
- Ideal State
11
In an arithmetic progression with first term 8 and common difference 5, find the sum of the first 13 terms.
Answer:
494
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 13/2 [2*8 + (13-1)*5]. 3. S_n = 494.
12
In an arithmetic progression with first term 9 and common difference 6, find the sum of the first 19 terms.
Answer:
1197
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 19/2 [2*9 + (19-1)*6]. 3. S_n = 1197.
13
In an arithmetic progression with first term 11 and common difference 7, find the sum of the first 17 terms.
Answer:
1139
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 17/2 [2*11 + (17-1)*7]. 3. S_n = 1139.
14
In an arithmetic progression with first term 8 and common difference 5, find the sum of the first 19 terms.
Answer:
1007
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 19/2 [2*8 + (19-1)*5]. 3. S_n = 1007.
15
In an arithmetic progression with first term 11 and common difference 6, find the sum of the first 13 terms.
Answer:
611
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 13/2 [2*11 + (13-1)*6]. 3. S_n = 611.
16
In an arithmetic progression with first term 10 and common difference 7, find the sum of the first 13 terms.
Answer:
676
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 13/2 [2*10 + (13-1)*7]. 3. S_n = 676.
17
In an arithmetic progression with first term 7 and common difference 5, find the sum of the first 12 terms.
Answer:
414
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 12/2 [2*7 + (12-1)*5]. 3. S_n = 414.
18
In an arithmetic progression with first term 11 and common difference 4, find the sum of the first 15 terms.
Answer:
585
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 15/2 [2*11 + (15-1)*4]. 3. S_n = 585.
19
In an arithmetic progression with first term 9 and common difference 4, find the sum of the first 18 terms.
Answer:
774
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 18/2 [2*9 + (18-1)*4]. 3. S_n = 774.
20
In an arithmetic progression with first term 7 and common difference 3, find the sum of the first 14 terms.
Answer:
371
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 14/2 [2*7 + (14-1)*3]. 3. S_n = 371.