Mathematics/General Ability MCQs
Topic Notes: Mathematics/General Ability
MCQs and preparation resources for competitive exams, covering important concepts, past papers, and detailed explanations.
Plato
- Biography: Ancient Greek philosopher (427–347 BCE), student of Socrates and teacher of Aristotle, founder of the Academy in Athens.
- Important Ideas:
- Theory of Forms
- Philosopher-King
- Ideal State
21
In an arithmetic progression with first term 8 and common difference 7, find the sum of the first 19 terms.
Answer:
1349
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 19/2 [2*8 + (19-1)*7]. 3. S_n = 1349.
22
In an arithmetic progression with first term 10 and common difference 4, find the sum of the first 16 terms.
Answer:
640
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 16/2 [2*10 + (16-1)*4]. 3. S_n = 640.
23
In an arithmetic progression with first term 6 and common difference 6, find the sum of the first 16 terms.
Answer:
816
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 16/2 [2*6 + (16-1)*6]. 3. S_n = 816.
24
In an arithmetic progression with first term 5 and common difference 5, find the sum of the first 18 terms.
Answer:
855
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 18/2 [2*5 + (18-1)*5]. 3. S_n = 855.
25
In an arithmetic progression with first term 7 and common difference 4, find the sum of the first 19 terms.
Answer:
817
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 19/2 [2*7 + (19-1)*4]. 3. S_n = 817.
26
In an arithmetic progression with first term 9 and common difference 5, find the sum of the first 12 terms.
Answer:
438
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 12/2 [2*9 + (12-1)*5]. 3. S_n = 438.
27
In an arithmetic progression with first term 5 and common difference 3, find the sum of the first 18 terms.
Answer:
549
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 18/2 [2*5 + (18-1)*3]. 3. S_n = 549.
28
In an arithmetic progression with first term 11 and common difference 6, find the sum of the first 18 terms.
Answer:
1116
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 18/2 [2*11 + (18-1)*6]. 3. S_n = 1116.
29
In an arithmetic progression with first term 6 and common difference 4, find the sum of the first 12 terms.
Answer:
336
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 12/2 [2*6 + (12-1)*4]. 3. S_n = 336.
30
In an arithmetic progression with first term 11 and common difference 5, find the sum of the first 16 terms.
Answer:
776
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 16/2 [2*11 + (16-1)*5]. 3. S_n = 776.