Physics MCQs
Topic Notes: Physics
MCQs and preparation resources for competitive exams, covering important concepts, past papers, and detailed explanations.
Plato
- Biography: Ancient Greek philosopher (427–347 BCE), student of Socrates and teacher of Aristotle, founder of the Academy in Athens.
- Important Ideas:
- Theory of Forms
- Philosopher-King
- Ideal State
31
What type of stress is produced when an applied force causes a change in the shape of a body without changing its volume?
Answer:
shearing stress
Shearing stress occurs when tangential forces are applied to a body, causing layers to slide over one another and changing the shape (angles) of the object while the volume remains constant. Tensile and compressive stresses involve changes in length, while bulk stress involves changes in volume.
32
Evaluate the following statements regarding Young's modulus and elasticity: 1. A higher Young's modulus indicates greater elasticity. 2. Steel is more elastic than copper.
Answer:
Both 1 and 2
Young's modulus measures a material's stiffness; a higher value means the material requires more stress to produce a given strain, which is the definition of being more elastic in physics. Steel has a higher Young's modulus than copper, meaning it returns to its original shape more effectively under stress, making it more elastic in the technical sense of the term.
33
Given four wires of the same material, which wire will experience the greatest elongation when subjected to the same tensile load?
Answer:
Wire of 3 m length and 1.5 mm diameter
Elongation (ΔL) is given by ΔL = (FL) / (AY), where A = πr². Elongation is directly proportional to length (L) and inversely proportional to the square of the diameter (d²). Comparing the ratios L/d², option C (3/1.5²) = 3/2.25 = 1.33, which is the highest value among the choices, leading to the greatest elongation.
34
Calculate the elastic potential energy stored in a steel wire (length 4m, area 3×10^-6m^2) stretched by 1mm, given a Young's modulus of 2×10^11 Nm^-2.
Answer:
0.75J
The energy stored in a stretched wire is given by U = (1/2) * (Y * A / L) * (ΔL)^2. Substituting the values: Y = 2×10^11, A = 3×10^-6, L = 4, and ΔL = 0.001. Calculating this yields U = 0.5 * (2×10^11 * 3×10^-6 / 4) * (0.001)^2 = 0.5 * (150,000) * 10^-6 = 0.075J. Note: The provided answer 0.75J appears to be a calculation error in the source.
35
Determine the Young's modulus of a rubber cord with a cross-sectional area of 2 cm^2 and a length of 1m, if a 10N tensile force causes a 1cm extension.
Answer:
5×106 Nm-2
Young's modulus (Y) is defined as Stress / Strain. Stress = Force / Area = 10 N / (2×10^-4 m^2) = 5×10^4 Pa. Strain = ΔL / L = 0.01 m / 1 m = 0.01. Y = (5×10^4) / 0.01 = 5×10^6 Nm^-2. This calculation confirms the provided answer.
36
Evaluate the following statements regarding elasticity and compressibility: 1. The SI unit of Young's modulus is N/m². 2. The reciprocal of bulk modulus is compressibility. 3. The compressibility of gases is very small. Which are correct?
Answer:
1 and 2
Young's modulus is measured in N/m² (Pascals). Compressibility is defined as the reciprocal of the bulk modulus. However, statement 3 is incorrect because gases are highly compressible, meaning their compressibility is very large, not small. Thus, only statements 1 and 2 are accurate.
37
How is the mass density of an object formally defined?
Answer:
Mass per unit volume
Mass density (often simply called density) is a physical property defined as the ratio of an object's mass to its volume. The standard SI unit for density is kilograms per cubic meter (kg/m^3). It describes how compactly the matter is packed within a given space.
38
What is the standard SI unit for the modulus of elasticity?
Answer:
Newton per square meter
The modulus of elasticity (Young's modulus) is defined as the ratio of stress to strain. Since strain is a dimensionless quantity (a ratio of lengths), the unit of the modulus of elasticity is the same as the unit of stress. Stress is defined as force per unit area, which is measured in Newtons per square meter (N/m^2) or Pascals (Pa).
39
In the context of Young's modulus, what is the relationship between the applied stress and the resulting strain when a material is under tension?
Answer:
Directly proportional to extension
Young's modulus is defined as the ratio of stress to strain. Within the elastic limit, stress is directly proportional to strain, which in turn is proportional to the extension of the material. While 'Directly proportional to strain' is technically more precise in physics, the provided answer 'Directly proportional to extension' is accepted here as it reflects the linear relationship between the applied force and the resulting physical deformation of the material.