Mathematics/General Ability MCQs
Topic Notes: Mathematics/General Ability
MCQs and preparation resources for competitive exams, covering important concepts, past papers, and detailed explanations.
Plato
- Biography: Ancient Greek philosopher (427–347 BCE), student of Socrates and teacher of Aristotle, founder of the Academy in Athens.
- Important Ideas:
- Theory of Forms
- Philosopher-King
- Ideal State
51
In an arithmetic progression with first term 7 and common difference 5, find the sum of the first 18 terms.
Answer:
891
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 18/2 [2*7 + (18-1)*5]. 3. S_n = 891.
52
In an arithmetic progression with first term 10 and common difference 6, find the sum of the first 12 terms.
Answer:
516
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 12/2 [2*10 + (12-1)*6]. 3. S_n = 516.
53
In an arithmetic progression with first term 9 and common difference 7, find the sum of the first 15 terms.
Answer:
870
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 15/2 [2*9 + (15-1)*7]. 3. S_n = 870.
54
In an arithmetic progression with first term 11 and common difference 4, find the sum of the first 17 terms.
Answer:
731
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 17/2 [2*11 + (17-1)*4]. 3. S_n = 731.
55
In an arithmetic progression with first term 11 and common difference 7, find the sum of the first 14 terms.
Answer:
791
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 14/2 [2*11 + (14-1)*7]. 3. S_n = 791.
56
In an arithmetic progression with first term 8 and common difference 7, find the sum of the first 14 terms.
Answer:
749
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 14/2 [2*8 + (14-1)*7]. 3. S_n = 749.
57
In an arithmetic progression with first term 8 and common difference 3, find the sum of the first 15 terms.
Answer:
435
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 15/2 [2*8 + (15-1)*3]. 3. S_n = 435.
58
In an arithmetic progression with first term 5 and common difference 7, find the sum of the first 14 terms.
Answer:
707
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 14/2 [2*5 + (14-1)*7]. 3. S_n = 707.
59
In an arithmetic progression with first term 7 and common difference 6, find the sum of the first 17 terms.
Answer:
935
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 17/2 [2*7 + (17-1)*6]. 3. S_n = 935.
60
In an arithmetic progression with first term 7 and common difference 3, find the sum of the first 17 terms.
Answer:
527
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 17/2 [2*7 + (17-1)*3]. 3. S_n = 527.