Mathematics/General Ability MCQs
Topic Notes: Mathematics/General Ability
MCQs and preparation resources for competitive exams, covering important concepts, past papers, and detailed explanations.
Plato
- Biography: Ancient Greek philosopher (427–347 BCE), student of Socrates and teacher of Aristotle, founder of the Academy in Athens.
- Important Ideas:
- Theory of Forms
- Philosopher-King
- Ideal State
61
In an arithmetic progression with first term 5 and common difference 5, find the sum of the first 13 terms.
Answer:
455
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 13/2 [2*5 + (13-1)*5]. 3. S_n = 455.
62
In an arithmetic progression with first term 9 and common difference 6, find the sum of the first 13 terms.
Answer:
585
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 13/2 [2*9 + (13-1)*6]. 3. S_n = 585.
63
In an arithmetic progression with first term 5 and common difference 4, find the sum of the first 17 terms.
Answer:
629
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 17/2 [2*5 + (17-1)*4]. 3. S_n = 629.
64
In an arithmetic progression with first term 9 and common difference 3, find the sum of the first 14 terms.
Answer:
399
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 14/2 [2*9 + (14-1)*3]. 3. S_n = 399.
65
In an arithmetic progression with first term 5 and common difference 5, find the sum of the first 16 terms.
Answer:
680
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 16/2 [2*5 + (16-1)*5]. 3. S_n = 680.
66
In an arithmetic progression with first term 10 and common difference 7, find the sum of the first 16 terms.
Answer:
1000
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 16/2 [2*10 + (16-1)*7]. 3. S_n = 1000.
67
In an arithmetic progression with first term 6 and common difference 3, find the sum of the first 13 terms.
Answer:
312
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 13/2 [2*6 + (13-1)*3]. 3. S_n = 312.
68
In an arithmetic progression with first term 8 and common difference 4, find the sum of the first 17 terms.
Answer:
680
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 17/2 [2*8 + (17-1)*4]. 3. S_n = 680.
69
In an arithmetic progression with first term 8 and common difference 4, find the sum of the first 12 terms.
Answer:
360
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 12/2 [2*8 + (12-1)*4]. 3. S_n = 360.
70
In an arithmetic progression with first term 9 and common difference 3, find the sum of the first 19 terms.
Answer:
684
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 19/2 [2*9 + (19-1)*3]. 3. S_n = 684.