Mathematics/General Ability MCQs
Topic Notes: Mathematics/General Ability
MCQs and preparation resources for competitive exams, covering important concepts, past papers, and detailed explanations.
Plato
- Biography: Ancient Greek philosopher (427–347 BCE), student of Socrates and teacher of Aristotle, founder of the Academy in Athens.
- Important Ideas:
- Theory of Forms
- Philosopher-King
- Ideal State
81
In an arithmetic progression with first term 11 and common difference 5, find the sum of the first 19 terms.
Answer:
1064
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 19/2 [2*11 + (19-1)*5]. 3. S_n = 1064.
82
In an arithmetic progression with first term 8 and common difference 6, find the sum of the first 12 terms.
Answer:
492
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 12/2 [2*8 + (12-1)*6]. 3. S_n = 492.
83
In an arithmetic progression with first term 8 and common difference 5, find the sum of the first 16 terms.
Answer:
728
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 16/2 [2*8 + (16-1)*5]. 3. S_n = 728.
84
In an arithmetic progression with first term 5 and common difference 6, find the sum of the first 17 terms.
Answer:
901
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 17/2 [2*5 + (17-1)*6]. 3. S_n = 901.
85
In an arithmetic progression with first term 5 and common difference 3, find the sum of the first 12 terms.
Answer:
258
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 12/2 [2*5 + (12-1)*3]. 3. S_n = 258.
86
In an arithmetic progression with first term 7 and common difference 4, find the sum of the first 13 terms.
Answer:
403
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 13/2 [2*7 + (13-1)*4]. 3. S_n = 403.
87
In an arithmetic progression with first term 6 and common difference 7, find the sum of the first 15 terms.
Answer:
825
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 15/2 [2*6 + (15-1)*7]. 3. S_n = 825.
88
In an arithmetic progression with first term 11 and common difference 4, find the sum of the first 12 terms.
Answer:
396
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 12/2 [2*11 + (12-1)*4]. 3. S_n = 396.
89
In an arithmetic progression with first term 6 and common difference 3, find the sum of the first 16 terms.
Answer:
456
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 16/2 [2*6 + (16-1)*3]. 3. S_n = 456.
90
In an arithmetic progression with first term 6 and common difference 7, find the sum of the first 12 terms.
Answer:
534
Step-by-step solution: 1. Use S_n = n/2 [2a + (n-1)d]. 2. S_n = 12/2 [2*6 + (12-1)*7]. 3. S_n = 534.