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The MCQs below are drawn from the Physics subject category.
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1451
In the set up shown the two slits S1 and S2 are not equidistant from the source S. The central fringe at O is then
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Explanation
If the slits are unequally illuminated the central fringe can be bright or dark depending on the source position and resulting phase difference.
1452
Conditions for interference are that the two sources should be coherent and :
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Explanation
For stable interference patterns, sources should be coherent and originate from closely related paths so they maintain a constant phase relationship.
1453
4. Which phenomenon can be observed with light waves, but not with sound waves?
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Explanation
Polarisation is a property of transverse waves like light; sound waves in air are longitudinal and do not exhibit polarization.
1454
A band of musicians is playing in the main street of a town. A person in the side street is most likely to hear prominently
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Explanation
Lower-pitched (longer wavelength) sounds diffract more around obstacles and into side streets, so low-pitched instruments are heard more prominently.
1455
Two sources of waves are called coherent if
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Explanation
Coherence requires a constant phase difference and same frequency (wavelength), not merely equal amplitudes or velocities.
1456
The condition for constructive interference of two coherent beams is that the path difference should be
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Explanation
Constructive interference occurs when the path difference equals an integer multiple of the wavelength (nλ).
1457
In case of constructive interference of two waves, the amplitude of the resultant wave is ______ either of the waves:
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Explanation
Constructive interference adds the displacements of the waves, producing a resultant amplitude greater than that of either wave.
1458
In case of YDS experiment, the distance between adjacent bright fringes is given by:
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Explanation
The block's explanatory answer indicates option A; the standard YDS fringe spacing formula is Ay = λL/d, matching A.
1459
In Young's double-slit experiment, for which colour the fringe width is least?
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Explanation
Fringe width is proportional to wavelength, so the shortest wavelength (blue) gives the least fringe width.
1460
In Michelson's Interferometer, the movable mirror is moved by 0.5000 mm and shift of 200 fringes is observed, the wavelength for light used is:
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Explanation
Using 2Δx = Nλ → λ = 2×0.5000×10^-3 m / 200 = 5×10^-6 m.