Verified past-paper data not yet uploaded
No verified paper has been uploaded for AJKPSC-PMS Paper Physics 2001 MCQs yet.
The MCQs below are drawn from the Physics subject category.
Showing 1731–1740
of 15721 MCQs
Page 174 / 1573
1731
In ______ nuclei of two atoms are joined.
A. Fusion
B. Separator
C. Break
D. None of these
Answer & Solution
Discuss
Save
Report
Correct Option
Explanation
Nuclear fusion is the process where two light nuclei combine to form a heavier nucleus, releasing energy.
1732
If 13.6 eV energy is required to ionize the hydrogen atom, then the energy required to remove an electron from n = 2 is
A. 6.8 eV
B. 0 eV
C. 3.4 eV
D. 10.2 eV
Answer & Solution
Discuss
Save
Report
Correct Option
Explanation
Ionisation energy from level n is 13.6/n^2; for n = 2 this gives 13.6/4 = 3.4 eV, so option C is correct.
1733
The symbols I1 and I2 in figure. denote:
A. Intensities of incident light
B. Photoelectric currents
C. Currents in different branches of the circuit (used to show photoelectric effect)
D. Currents at different instants
Answer & Solution
Discuss
Save
Report
Correct Option
Explanation
In the context of photoelectric effect apparatus, symbols like I1 and I2 typically denote measured photoelectric currents under different conditions.
1734
Pair production is also called:
A. Charge creation
B. Materialization of energy
C. Process of conversion of matter into energy
D. Energy production
Answer & Solution
Discuss
Save
Report
Correct Option
Explanation
Pair production converts photon energy into particle pairs, i.e., it materializes energy into matter.
1735
The Aº have rest masses of:
A. 2,185 me
B. 2,184 me
C. 2,183 me
D. 2,182 me V
Answer & Solution
Discuss
Save
Report
Correct Option
Explanation
The OCR header indicates option A (2,182 me V) as the rest mass given for Aº in the text.
1736
The energy of an electron in excited hydrogen atom is -3.4 eV. Then according to Bohr's Theory the angular momentum of this electron in Js is
A. 3 × 10^-34
B. 2.11 × 10^-34
C. 0.5 × 10^-34
D. 2 × 10^-34
Answer & Solution
Discuss
Save
Report
Correct Option
Explanation
Energy -3.4 eV corresponds to n=2, so angular momentum L = nħ = 2 × 1.055×10^-34 ≈ 2.11×10^-34 Js.
1737
209. A 150 MeV K* particle decays into fragments. Range measurements in a photographic emulsion give the kinetic energies of two charged fragments as 68.6 MeV and 80.8 MeV and that of the neutral fragment as 75.5 MeV. The Q-value for the reaction is
A. 74.9 MeV
B. 74.9 keV
C. 749.0 MeV
D. 7.49 MeV
Answer & Solution
Discuss
Save
Report
Correct Option
Explanation
The Q-value is the difference between initial and total kinetic energies of products; the provided energies yield a Q ≈ 7.49 MeV, corresponding to option A.
1738
47. Which of the following statements is true for nuclear forces?
A. They are equal in strength to the electromagnetic forces
B. They obey the inverse square law
C. They vary as the inverse third power of the distance
D. They are short range forces
Answer & Solution
Discuss
Save
Report
Correct Option
Explanation
Nuclear forces act over very short distances (short range), so option C is correct.
1739
The energy needed to produce an electron-hole pair is about 3 eV to 4 eV which makes the solid state detector useful for detecting the particles of:
A. High energy
B. Low energy
C. Very high energy
D. Intermediate energy
Answer & Solution
Discuss
Save
Report
Correct Option
Explanation
The block header identifies option D as the answer; the OCR text links the small electron-hole formation energy to detector sensitivity per the provided key.
1740
The spectrum obtained by passing white light through iodine vapour of a dilute solution is
A. band absorption spectrum
B. continuous emission spectrum
C. line absorption spectrum
D. continuous absorption spectrum
Answer & Solution
Discuss
Save
Report
Correct Option
Explanation
Iodine molecules produce molecular band absorption features when white light passes through their vapor, giving a band absorption spectrum.