Answer taken from provided answer hint in the block metadata.

At resonance the inductive and capacitive reactances cancel, leaving the series impedance equal to the resistance R.

Total voltage V = sqrt(Vr^2 + (Vl - Vc)^2) = sqrt(80^2 + (100-40)^2) = 100 V, so power factor = Vr / V = 80/100 = 0.8.

A semiconductor diode conducts significant current when forward biased, allowing charge carriers to cross the junction.

Inductance in electrical circuits plays a role analogous to mass in mechanics, resisting changes in current similar to mass resisting acceleration.

An emitter follower provides negative feedback that samples output voltage and feeds it in series with the input, characteristic of voltage-series feedback.

Push-pull amplifier stages use two transistors (one for each half-cycle) to drive the load, reducing distortion and increasing efficiency.

At steady state the inductor behaves as a short; current = emf / R = 50 V / 10 Ω = 5 A.

In a pure (intrinsic) semiconductor, increasing temperature increases carrier generation and thus reduces resistance.

Applied voltage = sqrt(200^2 + 150^2) = sqrt(40000+22500)=sqrt(62500)=250 V, so option B is correct.