Verified past paper — 10 questions
MCQs taken directly from the official verified paper record.
Showing 1–10
of 10 MCQs
Page 1 / 1
1
Which hybridization and molecular geometry best describe the central boron atom in BF3?
A. sp2; trigonal planar
B. sp3; tetrahedral
C. sp; linear
D. dsp2; trigonal bipyramidal
Answer & Solution
Discuss
Save
Report
Correct Option
Explanation
Boron forms three sigma bonds using sp2 hybrid orbitals with 120° angles and an empty p orbital, giving a trigonal planar geometry.
2
For a reaction with ΔH < 0 and ΔS < 0, under which condition is the reaction spontaneous (ΔG < 0)?
A. At all temperatures
B. At sufficiently low temperatures (T < ΔH/ΔS)
C. At sufficiently high temperatures (T > ΔH/ΔS)
D. Never spontaneous
Answer & Solution
Discuss
Save
Report
Correct Option
Explanation
With negative ΔH and ΔS, ΔG = ΔH − TΔS is negative only at low T; algebra gives spontaneity when T < ΔH/ΔS (ΔH/ΔS positive here).
3
In a weak acid–strong base titration, what is the pH at the half-equivalence point?
A. Equal to pKb of the conjugate base
B. Equal to 7.00 for all weak acids
C. Equal to the pKa of the weak acid
D. Equal to the equivalence point pH
Answer & Solution
Discuss
Save
Report
Correct Option
Explanation
At the half-equivalence point [HA] = [A−], so Henderson–Hasselbalch gives pH = pKa.
4
Which IR absorption is most characteristic of a carbonyl (C=O) functional group in a simple ketone?
A. Broad band around 3300 cm−1
B. Sharp band near 2100 cm−1
C. Band near 1600 cm−1
D. Strong sharp band near 1700 cm−1
Answer & Solution
Discuss
Save
Report
Correct Option
Explanation
Carbonyl groups give a strong, sharp stretching absorption typically near 1700 cm−1 in IR spectra.
5
In proton NMR, a hydrogen that has two equivalent neighboring hydrogens (n = 2) will appear as which multiplicity (ignoring long-range coupling)?
A. Triplet
B. Quartet
C. Doublet of doublets
D. Singlet
Answer & Solution
Discuss
Save
Report
Correct Option
Explanation
The N+1 rule gives multiplicity = n+1, so two equivalent neighbors produce a triplet (2+1 = 3).
6
According to Raoult's law, how does the partial vapor pressure of a volatile solvent change upon addition of a nonvolatile solute?
A. It increases proportional to the solute concentration
B. It equals the mole fraction of solvent multiplied by the vapor pressure of the pure solvent
C. It becomes independent of the solvent mole fraction
D. It equals the vapor pressure of the pure solvent regardless of solute
Answer & Solution
Discuss
Save
Report
Correct Option
Explanation
Raoult's law states P_solvent = X_solvent × P°_solvent, so the partial pressure is proportional to the solvent mole fraction.
7
Which pathway is most likely for the reaction of a tertiary alkyl chloride with water as solvent and nucleophile?
A. SN2 with backside attack
B. E2 elimination predominating
C. SN1 via a carbocation intermediate
D. Radical substitution
Answer & Solution
Discuss
Save
Report
Correct Option
Explanation
Tertiary substrates in polar protic solvents favor unimolecular ionization to a stabilized carbocation, leading to SN1 substitution by water.
8
If a galvanic cell has a positive standard cell potential (E°cell > 0), what is true about the standard Gibbs free energy change (ΔG°) and spontaneity of the cell reaction?
A. ΔG° > 0 and the reaction is non-spontaneous
B. ΔG° = 0 and the reaction is at equilibrium
C. ΔG° > 0 but the reaction is spontaneous
D. ΔG° < 0 and the reaction is spontaneous
Answer & Solution
Discuss
Save
Report
Correct Option
Explanation
ΔG° = −nFE°; a positive E° gives a negative ΔG°, so the reaction is spontaneous under standard conditions.
9
Which statement correctly describes the half-life of a first-order reaction?
A. It is independent of the initial concentration
B. It is directly proportional to the initial concentration
C. It decreases as the reaction proceeds
D. It equals the time for the concentration to drop by 75%
Answer & Solution
Discuss
Save
Report
Correct Option
Explanation
For first-order kinetics t1/2 = ln2/k, which does not depend on the initial concentration.
10
Why are tetrahedral transition-metal complexes more often high-spin compared with their octahedral counterparts for the same metal and ligands?
A. Tetrahedral complexes have stronger ligand fields
B. Tetrahedral splitting (Δtet) is smaller than octahedral splitting (Δoct), so pairing is less favorable
C. Tetrahedral geometry always enforces low-spin pairing
D. Tetrahedral complexes have no d-orbital splitting
Answer & Solution
Discuss
Save
Report
Correct Option
Explanation
Δtet ≈ 4/9 Δoct, so tetrahedral splitting is smaller and often insufficient to overcome pairing energy, leading to high-spin configurations.