On addition, result is rounded to least precise decimal place (one decimal from 2.1); 2.331+2.1 = 4.431 → 4.4 cm.

6.01 has 3 sig figs and 12 has 2 sig figs, so product must be reported to 2 sig figs: 6.01×12 = 72.12 → 72 m².

5.05 ×10^-27 has three significant digits (5,0,5); the others have more significant figures.

1.76 × 25 = 44.0; with 1.76 (3 significant figures) the result should be given as 44.0 cm3 (three significant figures).

Without additional notation (like a decimal point or bar), 5000 is ambiguous but typically has one definite significant figure.

The result should have the same significant figures as the least precise factor (current 3.23 has 3 sig figs), so 35.02935 → 35.0 (3 sig figs).

Radius '4 cm' has one significant figure, so volume (≈268.08 cm³) must be given to 1 significant figure → 3×10² cm³.

For addition, report to the least precise decimal place: 648 km has no decimals, so the sum must be given to the nearest km → 719 km.

Using the side 7.203 m and rounding results to appropriate significant figures yields surface area ≈ 311.3 m² and volume ≈ 373.7 m³, matching option A.

Total mass = 2.3 + 2×0.035 = 2.3 + 0.07 = 2.37 g; reported as 2.37 g per given options.