Solve the arithmetic expression: 10.0001 + 9.9999 - 8.9995
Option D
Adding the first two numbers produces exactly 20.0000. Subtracting 8.9995 from 20.0000 gives an end result of 11.0005.
Verified past-paper data not yet uploaded
No verified paper has been uploaded for GBPSC-PMS Paper Mathematics 2002 MCQs yet. The MCQs below are drawn from the Mathematics subject category.
Adding the first two numbers produces exactly 20.0000. Subtracting 8.9995 from 20.0000 gives an end result of 11.0005.
Rewrite y^5 as the product of the largest perfect square (y^4) and y. The square root of y^4 is y^2, bringing it outside the radical to get y^2*sqrt(y).
First simplify each radical: sqrt(12) is 2*sqrt(3) and sqrt(27) is 3*sqrt(3). Now that they have the same radicand, add them: 2*sqrt(3) + 3*sqrt(3) = 5*sqrt(3).
In the decimal number 0.06945, the digit 9 is located in the third position after the decimal point. This corresponds to the thousandths place, making its value 9/1000.
The scientific notation 3.14 * 10^6 signals shifting the decimal point precisely six places to the right side, translating logically to 3,140,000.
A fractional exponent of 1/2 is equivalent to taking the square root. The square root of 9 is 3, because 3 * 3 = 9.
To solve, express both sides with the same base. Since 16 is equal to 2^4, the equation becomes 2^x = 2^4. Thus, the exponents must be equal, making x = 4.
Count the number of zeroes in 10000 to find its power of 10. There are four zeroes, so 10000 is 10^4. Therefore, from 10^x = 10^4, x must be 4.
Since 9/4 is equivalent to the decimal 2.25, adding 2.25 to 1.75 correctly equals 4.0. Therefore, asserting that their sum equals 5 is entirely incorrect.
To determine how many times greater it is, divide 0.1 by 0.01. The result of 0.1 ÷ 0.01 is 10, meaning 0.1 is 10 times larger than 0.01.