May 2025 Edition
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May 2025 Current Affairs MCQs & Solutions
Top national & international current affairs questions for CSS, PMS, FPSC, PPSC, and NTS screening tests.
#2121
The average of 30 numbers is zero. At most, how many of these numbers may be greater than zero?
(b) 1
(c) 15
(d) 29
Explanation: For the average of 30 numbers to be zero, their total sum must be zero. It is possible for 29 numbers to be strictly greater than zero (positive), as long as the 30th number is a sufficiently large negative number to cancel out their sum. Thus, at most 29 can be greater than zero.
#2122
A vessel is filled with liquid, 3 parts of which are water and 5 parts syrup. How much of the mixture must be drawn off and replaced with water so that the mixture may be half water and half syrup?
(a) 1/3
(b) 1/4
(c) 1/5
(d) 1/7
Explanation: Initial syrup fraction = 5/8. We want final syrup fraction = 1/2. Let fraction x be replaced. Syrup left = (5/8)*(1 - x). (5/8)(1 - x) = 1/2 => 1 - x = 4/5 => x = 1/5.
#2123
A starts a business with an investment of Rs. 25000. After 3 months, B joins with Rs. 30000 and after another 3 months, C joins with Rs. 40000. If the total profit at the end of the year is Rs. 20250, what is the share of C?
(a) Rs. 5000
(b) Rs. 6000
(c) Rs. 6500
(d) Rs. 7000
Explanation: Time for A = 12 months, B = 9 months, C = 6 months. Ratio = (25000*12) : (30000*9) : (40000*6) = 300 : 270 : 240 = 10 : 9 : 8. Total parts = 27. C's share = (8/27) * 20250 = 8 * 750 = Rs. 6000.
#2124
A starts a business with an investment of Rs. 25000. After 3 months, B joins with Rs. 30000 and after another 3 months, C joins with Rs. 40000. If the total profit at the end of the year is Rs. 20250, what is the share of C?
(a) Rs. 5000
(b) Rs. 6000
(c) Rs. 6500
(d) Rs. 7000
Explanation: Time for A = 12 months, B = 9 months, C = 6 months. Ratio = (25000*12) : (30000*9) : (40000*6) = 300 : 270 : 240 = 10 : 9 : 8. Total parts = 27. C's share = (8/27) * 20250 = 8 * 750 = Rs. 6000.
#2125
In what ratio must a grocer mix two varieties of tea worth Rs. 60 a kg and Rs. 65 a kg so that by selling the mixture at Rs. 68.20 a kg he may gain 10%?
(a) 3:2
(b) 3:4
(c) 3:5
(d) 4:5
Explanation: Step 1: Find the Cost Price (CP) of the mixture. SP = 68.20, Profit = 10%. CP = 68.20 / 1.10 = Rs. 62 per kg. Step 2: Use alligation with C = 60, D = 65, M = 62. Step 3: Ratio = (65 - 62) : (62 - 60) = 3 : 2.
#2126
How many kg of sugar costing Rs. 9 per kg must be mixed with 27 kg of sugar costing Rs. 7 per kg so that there may be a gain of 10% by selling the mixture at Rs. 9.24 per kg?
(a) 36 kg
(b) 42 kg
(c) 54 kg
(d) 63 kg
Explanation: Step 1: CP of mixture = SP / 1.10 = 9.24 / 1.10 = Rs. 8.40. Step 2: Alligation on Rs. 9 and Rs. 7 to get Rs. 8.40. Ratio = (8.40 - 7) : (9 - 8.40) = 1.40 : 0.60 = 7 : 3. Step 3: The ratio of Rs. 9 sugar to Rs. 7 sugar is 7:3. Let quantity of Rs. 9 sugar be x. x / 27 = 7 / 3 -> x = 63 kg.
#2127
A vessel is filled with liquid, 3 parts of which are water and 5 parts syrup. How much of the mixture must be drawn off and replaced with water so that the mixture may be half water and half syrup?
(a) 1/3
(b) 1/4
(c) 1/5
(d) 1/7
Explanation: Step 1: Initial syrup = 5/8. Target syrup = 1/2. Step 2: Let x be the fraction of mixture drawn off. The fraction of original syrup remaining is (1 - x). Step 3: (5/8) * (1 - x) = 1/2 -> 1 - x = 4/5 -> x = 1/5.
#2128
How many kg of salt at 42 paise per kg must a man mix with 25 kg of salt at 24 paise per kg so that he may on selling the mixture at 40 paise per kg gain 25%?
(a) 15 kg
(b) 20 kg
(c) 25 kg
(d) 30 kg
Explanation: Step 1: CP of mixture = 40 / 1.25 = 32 paise. Step 2: Alligation of 42p and 24p to get 32p. Ratio = (32 - 24) : (42 - 32) = 8 : 10 = 4 : 5. Step 3: 4/5 = x / 25 -> x = 20 kg.
#2129
How many kg of wheat costing Rs. 8 per kg must be mixed with 36 kg of wheat costing Rs. 5.40 per kg so that a 20% gain may be obtained by selling the mixture at Rs. 7.20 per kg?
(a) 10.8 kg
(b) 12 kg
(c) 14.4 kg
(d) 15 kg
Explanation: Step 1: CP of mixture = 7.20 / 1.2 = 6. Step 2: Alligation: 8 and 5.40, mean 6. Ratio = (6 - 5.40) : (8 - 6) = 0.60 : 2 = 3 : 10. Step 3: 3 / 10 = x / 36 -> 10x = 108 -> x = 10.8 kg.
#2130
A grocer buys two kinds of rice at Rs. 18 and Rs. 24 per kg respectively. In what ratio should these be mixed so that by selling the mixture at Rs. 24 per kg, 20% may be gained?
(a) 1:2
(b) 2:1
(c) 3:2
(d) 2:3
Explanation: SP of mixture = 25.20. Gain = 20%. CP of mixture = 25.20 / 1.20 = Rs. 21 per kg. Using alligation: Quantity of cheaper / Quantity of dearer = (24 - 21) / (21 - 18) = 3 / 3 = 1:1. Let me re-read the numbers. Cheap=18, Dear=24. Mix CP=21. (24-21)/(21-18) = 3/3 = 1:1. Wait, let me adjust the options or the question. If SP = 26.40, CP = 22. Ratio = (24-22)/(22-18) = 2/4 = 1:2. If SP = 25.2, CP = 21. Ratio = 1:1. I will change the SP to Rs. 25.2 so it's 1:1? Let's use SP = 24. CP = 20. Ratio = (24-20)/(20-18) = 4/2 = 2:1. Question: SP=24, Gain 20%. CP=20.
#2131
What is the simple interest on Rs. 2500 at 6% p.a. from 4th March to 16th May in the same year?
(a) Rs. 25
(b) Rs. 30
(c) Rs. 35
(d) Rs. 40
Explanation: Calculate the number of days: March (31-4) = 27 days, April = 30 days, May = 16 days. Total = 73 days. Time T = 73/365 = 1/5 years. SI = (2500 × 6 × 1/5) / 100 = (500 × 6) / 100 = Rs. 30.
#2132
If 1st May of a year is Tuesday, what day is 1st June of the same year?
(a) Thursday
(b) Friday
(c) Saturday
(d) Sunday
Explanation: May has 31 days. The number of odd days in May is 31 mod 7 = 3. Moving from 1st May to 1st June adds these 3 odd days to the current day. Tuesday + 3 days = Friday.
#2133
How many days are there from 26th January 2008 to 15th May 2008 (both days included)?
(a) 110
(b) 111
(c) 112
(d) 113
Explanation: 2008 is a leap year, so February has 29 days. Days = Jan (31 - 26 + 1 = 6) + Feb (29) + Mar (31) + Apr (30) + May (15) = 6 + 29 + 31 + 30 + 15 = 111 days.
#2134
What is the day on 10th May 1857?
(a) Sunday
(b) Monday
(c) Tuesday
(d) Saturday
Explanation: 1856 years = 1600(0) + 200(3) + 56(14 LY + 42 NY = 28+42=70 = 0 odd). Total up to 1856 = 3 odd days. 1857 is NY. Jan to May 10 = 3+0+3+2+10 = 18 = 4 odd days. Total = 3+4 = 7 = 0 odd days. Day 0 is Sunday.
#2135
If 4th November 2024 is a Saturday, what will be the day on 4th November 2025?
(a) Sunday
(b) Monday
(c) Tuesday
(d) Wednesday
Explanation: Wait, 2024 is a leap year, but February 29th has already passed by November. Moving from Nov 2024 to Nov 2025 crosses February 2025, which has 28 days (ordinary year). This is 365 days, yielding 1 odd day. Wait, my option logic was Monday? Saturday + 1 = Sunday. Let me correct the options to have Sunday as correct.
#2136
What day of the week was 28th May 2006?
(a) Sunday
(b) Monday
(c) Tuesday
(d) Wednesday
Explanation: 2005 years = 2000(0) + 5(1 LY + 4 NY = 2+4=6 odd days). 2006 is NY. Jan to May 28 = 3+0+3+2+28 = 36 = 1 odd day. Total = 6+1 = 7 = 0 odd days. Day 0 is Sunday.
#2137
Which day of the week was 6/9/2025?
(a) Tuesday
(b) Saturday
(c) Monday
(d) Wednesday
Explanation: Step-by-step solution: 1. Use Zeller's congruence to compute the day of the week. 2. After substituting the values, remainder corresponds to Saturday. 3. Therefore, 6/9/2025 fell on a Saturday.
#2138
Which day of the week was 27/8/2025?
(a) Wednesday
(b) Monday
(c) Thursday
(d) Tuesday
Explanation: Step-by-step solution: 1. Use Zeller's congruence to compute the day of the week. 2. After substituting the values, remainder corresponds to Wednesday. 3. Therefore, 27/8/2025 fell on a Wednesday.
#2139
Which day of the week was 27/12/2025?
(a) Monday
(b) Wednesday
(c) Tuesday
(d) Saturday
Explanation: Step-by-step solution: 1. Use Zeller's congruence to compute the day of the week. 2. After substituting the values, remainder corresponds to Saturday. 3. Therefore, 27/12/2025 fell on a Saturday.
#2140
Which day of the week was 13/2/2025?
(a) Tuesday
(b) Thursday
(c) Wednesday
(d) Monday
Explanation: Step-by-step solution: 1. Use Zeller's congruence to compute the day of the week. 2. After substituting the values, remainder corresponds to Thursday. 3. Therefore, 13/2/2025 fell on a Thursday.