Volume ∝ r^3 so percentage error = 3*(Δr/r)*100 = 3*(0.1/4.3)*100, which is option B.

8% of 6.2 is 0.496, which rounds to 0.5, so the uncertainty is ±0.5 Ω.

Volume ∝ r^3, so percentage error in volume ≈ 3 × (percentage error in radius) = 3 × 1% = 3%.

When adding or subtracting quantities, their absolute uncertainties are combined by addition.

Accounting for buoyancy of air yields a very small fractional change; the worked solution in the OCR shows option (a) as the result giving 0.005%.

Dimensional analysis with m ∝ ρ^a g^b u^c yields a=1, b=-3, c=6, so m ∝ u^6 (with appropriate dependence on ρ and g).

Work, energy and torque share dimensions [M L^{2} T^{-2}], while pressure has different dimensions [M L^{-1} T^{-2}].

Work and energy share dimensions, and force and weight are both forces with same dimensions; thus both statements are correct.

Torque is force times distance: [M L T^{-2}] × [L] = [M L^{2} T^{-2}].

Angular velocity has dimensions of inverse time, [T^-1], since it is angle per unit time.