Option A
Multiply the numbers inside the roots to get sqrt(100). The principal square root of 100 is 10, completing the simplification.
HEC (Higher Education Commission) · LAT
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Number System & Operations · Mathematics-General Ability
Multiply the numbers inside the roots to get sqrt(100). The principal square root of 100 is 10, completing the simplification.
To isolate x, perform the inverse operation of a square root by squaring both sides of the equation. Squaring 5 gives 25, so x = 25.
Applying the exponent rule for division, subtract the exponent 4 from the exponent 6 while maintaining the base of 5. This results in 5^2.
Raising a number to the power of 1/3 is the same as finding its cube root. The cube root of 8 is 2, because 2^3 = 8.
Subtracting the exponents 8 - 7 gives 1. Any variable raised to the power of 1 is just the variable itself, so a^1 is written simply as a.
Multiplying a square root by itself cancels out the radical, effectively squaring the square root. sqrt(6) * sqrt(6) is sqrt(36), which immediately simplifies to 6.
The bounds are 3/4 = 0.75 and 5/6 ≈ 0.833. Analyzing the options: 1/2 = 0.50, 2/3 ≈ 0.667, 4/5 = 0.80, and 9/10 = 0.90. The only fraction falling within the 0.75 to 0.833 range is 4/5.
Multiply numerator and denominator by sqrt(3) to rationalize. This gives (3*sqrt(3)) / 3. The 3s cancel out, leaving just sqrt(3).
The boundaries correspond to roughly 0.333 and 0.875. Evaluating the options gives: 1/4 = 0.25, 23/24 ≈ 0.958, 11/12 ≈ 0.917, and 17/24 ≈ 0.708. Only 17/24 sits correctly within this boundary.
There are 3600 seconds in one hour (60 minutes × 60 seconds). Therefore, one second is 1/3600 of an hour, which mathematically evaluates to approximately 0.000277... or rounded to 0.00027.
To remove the cube root, cube both sides of the equation. The cube of 3 is 3 * 3 * 3, which equals 27. Therefore, x = 27.
Look for a perfect cube factor of 16, which is 8. Writing cbrt(16) as cbrt(8 * 2) allows us to bring out the cube root of 8 (which is 2), yielding 2*cbrt(2).
The largest perfect square that divides 27 is 9. We can write sqrt(27) as sqrt(9 * 3). The square root of 9 is 3, making the simplified form 3*sqrt(3).
The valid interval boundaries are 7/13 (≈ 0.538) and 4/5 (0.80). Checking the values: 1/2 = 0.5 (falls below 0.538), 2/3 ≈ 0.667, 3/4 = 0.75, 5/7 ≈ 0.714. Hence, 1/2 does not belong inside the targeted range.
A negative exponent means taking the reciprocal of the base and making the exponent positive. So, 2^-3 becomes 1/(2^3), which evaluates to 1/8.
Step-by-step solution: 1. Align the decimal points for both numbers. 2. Add 7.3 + 0.68 = 7.98. 3. Ensure the result is rounded to three decimal places.
Step-by-step solution: 1. Ignore the decimal points and multiply as whole numbers. 2. Count the total decimal places (three) and place the decimal accordingly. 3. The product is 0.546.
Step-by-step solution: 1. Align the decimal points for both numbers. 2. Add 8.1 + 0.76 = 8.86. 3. Ensure the result is rounded to three decimal places.
Step-by-step solution: 1. Align the decimal points for both numbers. 2. Add 8.3 + 0.78 = 9.08. 3. Ensure the result is rounded to three decimal places.
Step-by-step solution: 1. Align the decimal points for both numbers. 2. Add 10.7 + 1.02 = 11.72. 3. Ensure the result is rounded to three decimal places.