Number Series MCQs with Answers & Explanations

The terms follow the operation: \times 1 + 1, \times 2 + 2, \times 3 + 3, \times 4 + 4. Continuing this pattern, (136 \times 5) + 5 = 680 + 5 = 685.

Each term is divided by 5: 1000 \div 5 = 200, 200 \div 5 = 40, and 40 \div 5 = 8.

The differences between consecutive numbers form a Fibonacci-like pattern: +2, +3, +5, +7, +11 (prime numbers). Adding the next prime, 13, to 30 gives 30 + 13 = 43.

The numbers are consecutive prime numbers. The prime number immediately following 37 is 41.

Each term is obtained by doubling the preceding number and subtracting 1: (33 \times 2) - 1 = 66 - 1 = 65. Alternatively, the differences double each time: +2, +4, +8, +16, +32 (33 + 32 = 65).

The sequence alternates between adding 2 and adding 4: +2, +4, +2, +4, +2. The next step is adding 4: 25 + 4 = 29.

The sequence follows n^3 - 1: 1^3 - 1 = 0, 2^3 - 1 = 7, 3^3 - 1 = 26, 4^3 - 1 = 63, 5^3 - 1 = 124. For n = 6, 6^3 - 1 = 216 - 1 = 215.

The sequence follows n^3 + 1: 1^3 + 1 = 2, 2^3 + 1 = 9, 3^3 + 1 = 28, 4^3 + 1 = 65, 5^3 + 1 = 126. For n = 6, 6^3 + 1 = 216 + 1 = 217.

The sequence follows the formula 2 \times n^2: 2 \times 1^2 = 2, 2 \times 2^2 = 8, 2 \times 3^2 = 18, 2 \times 4^2 = 32, 2 \times 5^2 = 50. For n = 6, 2 \times 6^2 = 2 \times 36 = 72.

The sequence is an arithmetic progression with a common difference of -5: 30 - 5 = 25.

The sequence represents square pyramidal numbers, formed by adding consecutive squares: 1, 1+4=5, 5+9=14, 14+16=30, 30+25=55, 55+36=91. Adding 7^2 = 49 yields 91 + 49 = 140.

The terms represent n^2 - 1 in descending order starting from n = 11: 11^2 - 1 = 120, 10^2 - 1 = 99, 9^2 - 1 = 80, 8^2 - 1 = 63, 7^2 - 1 = 48. For n = 6, 6^2 - 1 = 36 - 1 = 35.

Each term is multiplied by 2 and then increased by an incrementing value (+1, +2, +3): (6 \times 2) + 1 = 13, (13 \times 2) + 2 = 28, (28 \times 2) + 3 = 59. The next term is (59 \times 2) + 4 = 118 + 4 = 122.

The differences between consecutive numbers increase by 1 each time: +1, +2, +3, +4, +5. Next is +6, giving 16 + 6 = 22.

The division factor increases by 1 at each step: \div 2, \div 3, \div 4. The next step is 10 \div 5 = 2.

Each number is multiplied by 1.5 (3/2): 4 \times 1.5 = 6, 6 \times 1.5 = 9, 9 \times 1.5 = 13.5. Then 13.5 \times 1.5 = 20.25.

The sequence follows n(n + 2) for n = 1, 2, 3, 4, 5. For n = 6, 6 \times 8 = 48. Alternatively, consecutive odd numbers are added: +5, +7, +9, +11, +13 (35 + 13 = 48).

The differences between terms are consecutive square numbers: +1^2 (+1), +2^2 (+4), +3^2 (+9), +4^2 (+16). Adding 5^2 (+25) to 32 yields 32 + 25 = 57.

The differences double at each step: +2, +4, +8, +16. Adding 32 to 37 gives 37 + 32 = 69.

The pattern is: (5 \times 2) + 1 = 11, (11 \times 2) + 2 = 24, (24 \times 2) + 3 = 51, (51 \times 2) + 4 = 106. Next is (106 \times 2) + 5 = 212 + 5 = 217.